Easy Problems
Number One
First, you would realize that the problem is a cosine graph. The next thing you would do is find the period of the graph. You would then put B, which is 2pi, under 2pi. The two 2pi's would cancel out leaving you with 1. To find the intervals of your graph, you would put 1/4, giving you your intervals, going up fourths until you reach 1. Since the number before cos is 1, your amplitude is 1. You would go up one and down one from zero. A cosine graph starts at the top if it is positive, so your first dot would be at (0,1). Since that would be your first dot and you need 5 dots, you follow the intervals and your next dot would be at (1/4,0). Your following dots would be at (2/4,-1/2), (3/4,0), and (1,1). If you got that, then you are right on track to figuring it out.
Number Two
This graph is a sine graph. A sine graph starts in the middle and goes up first and then back down. Just like a cosine graph, you would find the period. Also like a cosine graph, you would put 2pi over B. In this equation B would be 3. If you put 2pi/3, then that would be your period. Next, find the intervals. You would do 2pi/3/4. Because you can't have a fraction over a fraction, you would flip and multiply. The bottom was 4/1, but when you F&M, it then becomes 1/4. You would multiply 2pi/3 by 1/4. On the top would be 2pi and on the bottome would be 12. Both the top and bottom can be divided by 2 leaving the interval to be pi/6. Also, if you look before the sine, there is a 1. That is the amplitude. Once again, you would go up 1 and down 1. A sine graph that has an amplitude of 1 and is not negative, starts at (0,0). That is also where this graph starts. You follow the intervals and go up and down. The dots following the first are (pi/6,1), (2pi/6,0), (3pi/6,-1), and (4pi/6,0). The latter reduces to 2pi/3, which is the period. For a full period, there are 5 dots and hopefully you got all of them.
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